A) Find the energy needed to heat a tank holding water of 60 kg to rise the temperature from 10 degree Celsius to 60 degree Celsius (c=4200 j/Koc) b)find the time for rising this much temperature if the power of heater is 3kW

a) Q = 12600000 [J]

b) t = 4200 [s] or 70 [min]

Explanation:

To solve this problem we must use the following equation that is defined as the heat equation, this equation relates the mass to the specific heat and temperature changes.

Q = m*Cp*(T_f - T_i)

where:

Q = energy as heat [J] (units of Joules)

Cp = specific heat = 4200 [J/Kg * °C]

T_f = final temperature = 60 [°C]

T_i = initial temperature = 10 [°C]

m = mass = 60 [kg]

Q = 60*4200*(60 - 10)

Q = 12600000 [J]

b)

To calculate the time, we know that the power is equal to the energy generated over the given time.

P = Q/t

where:

P = power = 3000 [W]

t = time [s]

t = Q/P

t = 12600000/3000

t = 4200 [s] or 70 [min]

heats surface water up

  the unit of the measure =

explanation:

  the property that is quantified by the energy needed per of material to raise the temperature by one.

  si unit of energy = joule (j)

  si unit of temperature = kelvin (k)

  si unit of mass of material = kilogram (kg)

the property that is quantified by the energy needed per of material to raise the temperature by one is called specific heat.

the unit of specific heat is