A spring compresses 0.8 m when the 800 kg crate of llamas slides down and hits it. Ignore friction and find the spring constant of the spring. The ramp is at a 47° angle.

7167.27N/m

Explanation:

To get the force constant k, we will use the formula;

F = kx where

F is the force acting on the object down the plane

k is the spring constant

x is the extension

The force acting down the ramp us F = Wsintheta. The formula will become;

Wsintheta = kx

mgsintheta = kx

K = mgsintheta/x

K = (800)(9.8)sin47°/0.8

K= 7840sin47°/0.8

K = 5733.81/0.8

K = 7167.27N/m

Hence the spring constant of the spring is 7167.27N/m

i think the answer is tomato juice? not entirely sure though