A student walks 20 m east, 40 m north, and then 20 m west. What are the student's distance traveled and displacement?

Total distance = 80 m

Total displacement = 40 m north

Explanation:

Total distance = 20 m + 40 m + 20 m

Total distance = 80 m

Total displacement = 20 m east - 20 m west + 40 m north

Total displacement = 40 m north

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.

the ima (higher than 1m) will be greater than the ima with the height of 1m.