What is the period of revolution of a satellite with mass m that orbits the earth in a circular path of radius 7880 km (about 1500 km above the earth’s surface)? G = 6.674 × 10−11 Nm2/kg2 and mE = 5.97 × 1024 kg. A. 100 min
B. 90 min
C. 116 min
D. 105 min

okay i have so many questions. but the big one here is: um wt..f is this mess? ?

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form

0 = 0.40 / 0 = 0

= 0.20 = 9.80 ⁄2 =?

=0 , = = 0.20 =0.50 0 0.40 ⁄

=0−122 =0−12(9.80 ⁄2)(0.50)2 =1.2