An object accelerates from rest to 85 m/s over a distance of 36 m. What acceleration did it experience?

Explanation:

Given:-

Initial velocity (u) = 0m/s

Final velocity (v) = 85m/s

Distance covered (s) = 36m

To Find:-

Acceleration of the object (a)

Solution:-

By using 3rd equation of motion

→ v² = u² +2as

Substitute the value we get

→ 85² = 0² +2×a×36

→ 7225 = 0 + 72 ×a

→ a = 7225/72

→ a = 100.34m/s²

∴ The acceleration of the object is 100.34m/s²

Additional Information!!

The rate of change of velocity at per unit time is called acceleration .

✧ SI unit of acceleration is m/s²

✧ It is vector Quantity ( both magnitude and directio

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