A 2.25 kg ball experiences a net force of 965 N up a ramp as shown. Once the ball reaches the top of the ramp, the force no longer acts. The force acts over a distance of 1.50 m on the
ramp. Find the horizontal distance x that the ball travels
before it hits the deck. The top of the ramp is 4.50
meters above the deck below.

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s