A small sculpture made of gold ( rho gold =19320 kg/m^ 3 ) is believed to have a secret central cavity. The weight of the sculpture in air is 11.29 N. When it is submerged in water, the weight is 9.190 N. What is the volume of the secret cavity?

1.1 x 10⁻⁵m³

Explanation:

Given parameters:

Weight in air  = 11.29N

Weight in water  = 9.190N

Density of gold  = 19320kg/m³

Unknown:

Volume of the secret cavity = ?

Solution:

To solve this problem, we need to find the mass of the secret cavity.

Weight of the cavity  = Weight of sculpture in air  - Weight of sculpture in water

 Weight of cavity  = 11.29N  -  9.190N = 2.1N

 Weight  = mass x acceleration due to gravity

        Mass  =   = 0.2kg

So;

 Volume of substance can be determined from the density.

 Density  =  

   Volume  =  

 Now insert the parameters and solve;

  Volume  =   = 1.1 x 10⁻⁵m³

the force on the thing and the distance the force moves the thing

when a device is used in a circuit in which the voltage is 81 v, the current flowing through the device is 3 a. what is the resistance of the device?

a. 27 ω

b. 40.5 a

c. 243 ω

d. 243 a

the correct answer is a. 27