Justin strikes a 0.058-kg golf ball with a force of 260 N. If the ball moves with a velocity of 63 m/s, calculate the time the ball is in contact with the club

0.014s

Explanation:

Given parameters:

Mass of the ball  = 0.058kg

Force  = 260N

Velocity of the ball  = 63m/s

Unknown:

Time of contact  = ?

Solution:

To solve this problem, we apply Newton's second law of motion which is mathematically expressed as;

    Ft  = m(v - u)

F is the force

t is time

m is the mass

v is the final velocity

u is the initial velocity = 0m/s

   Insert the parameters and find t;

      260 x t  = 0.058(63 - 0)

       260t  = 3.65

            t = 0.014s

the answer is c. the lower legs are levers, and the knees are fulcrums. the ankles hold the loads.