Calculate the height from which a body is released from rest if its velocity just before hitting the ground is 30 meter per seconds?

Explanation:

u = 0m/s

v = 30m/s

a = g = 10m/s²

s = H = ?

using the formula,

v² = u² + 2as

30² = 0² + 2(10)(H)

900 = 20H

H = 900/20

H = 45m

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west