NEED A PHYSICS EXPERT TO HELP ME PLS I've been stuck on this for two hours:

Water flows steadily from an open tank as shown in the figure. (Figure 1)The elevation of point 1 is 10.0 m , and the elevation of points 2 and 3 is 2.00 m . The cross-sectional area at point 2 is 4.80×10−2 m2 ; at point 3, where the water is discharged, it is 1.60×10−2 m2 . The cross-sectional area of the tank is very large compared with the cross-sectional area of the pipe.

Assuming that Bernoulli's equation applies, compute the volume of water ΔV that flows across the exit of the pipe in 1.00 s . In other words, find the discharge rate ΔV/Δt.
Express your answer numerically in cubic meters per second.

The discharge rate of water (Q) that flows across the exit of the pipe in 1.00 seconds is 0.200 .

Given the following data:

To find the discharge rate of water (Q) that flows across the exit of the pipe in 1.00 seconds assuming that Bernoulli's equation applies:

In this exercise, we would apply Torricelli's Law, which states that the speed of the efflux in an apparatus, under the force of gravity is directly proportional to the square root of the height of the fluid above it.

Mathematically, Torricelli's Law is given by the formula:

Where:

Substituting the given parameters into the formula, we have;

Speed, V = 12.52 m/s

Now, we can find the discharge rate of the pipe:

Discharge rate, Q = 0.200

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