A spring is 17 cm long when it is lying on a table. One end is then attached to a hook and the other end is pulled by a force that increases to 25 N, causing the spring to stretch to a length of 19.2 cm. How much work was required to stretch the spring? A. 3.13 J
B. 0.552 J
C. 1.67 J
D. 0.276 J

im pretty sure it B but I recommend waiting for another person. I used the workdone formula (Force*Dictance*cos(theta) and got 55 Joules

Explanation:

D. 0.276 J

Explanation:

When I solved this, I got 0.275, so I chose the one closest.

To solve:

convert 17 cm and 19.2 cm to 0.17 m and 0.192 m

W(on spring) = 1/2 (0.192 m - 0.17 m)(25N)

                     = 1/2 (.022 m)(25 N)

                     = 0.275

force is based upon mass and acceleration.the statement is not always true.

it can be explained from newton's second law of motion.

as per newton's second law of motion the rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.

mathematically it can be written as -

                                              ⇒      

here   k is the proportionality constant whose value is 1.

                                                            [a is the acceleration=dv/dt]

hence we see that force not only depends on mass and acceleration but also on velocity and rate of change of mass. force f will depend on mass and acceleration only when mass is constant.

hence the statement that force is based upon mass and acceleration is false.

snell's law

refractve index = sin incidence / sin refraction