A 1000-kg car traveling with a speed of 35 m/s skids to a stop in 25m. Determine the average force applied to the breaks. If it took 3.2s to stop, who much power was generated by the breaks?

1. 24500 N.

2. 191406.25 watt

Explanation:

From the question given above, the following data were obtained:

Mass (m) of car = 1000 Kg

Initial velocity (u) = 35 m/s

Distance (s) = 25 m

Final velocity (v) = 0 m/s

Time (t) = 3.2 s

Force (F) =?

Power (P) =?

Next, we shall determine the acceleration of the car. This can be obtained as follow:

Initial velocity (u) = 35 m/s

Distance (s) = 25 m

Final velocity (v) = 0 m/s

Acceleration (a) =?

v² = u² + 2as

0 = 35² + (2 × a × 25)

0 = 1225 + 50a

Collect like terms

0 – 1225 = 50a

– 1225 = 50a

Divide both side by 50

a = – 1225 / 50

a = –24.5 m/s²

1. Determination of the force.

Mass (m) of car = 1000 Kg

Acceleration (a) = –24.5 m/s²

Force (F) =?

F = m × a

F = 1000 × –24.5

F = –24500 N

The negative sign indicate that the force is in opposite direction to the motion of the car.

2. Determination of the power

Force (F) = 24500 N

Distance (s) = 25 m

Time (t) = 3.2 s

Power (P) =?

Next, we shall determine the energy.

Energy = force × distance

Energy = 24500 × 25

Energy = 612500 J

Finally, we shall determine the power. This is illustrated below:

Power = Energy /time

Power = 612500 /3.2

Power = 191406.25 watt

this is an example of "committed" time.

committed time, as contracted time, takes need over essential and available time since it is seen as profitable work. it alludes to the time allotted to keep up a home and family. at the point when a man is commuting using committed time this individual may feel that the drive is an obligation to family, for example, strolling youngsters to class or driving a mate to work. contracted and committed time clients may feel that their commute could really compare to the commute of important or leisure time clients on the grounds that their commute is profitable work. in this manner, they might be more disposed to pick a mechanized method of movement.  

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