An object of mass(0.8kg) is attached to massless string of length (2.0),and swung with a tangential velocity of (3.0m/s) what is the tension in the string?

3.6 N

Explanation:

The magnitude of centripetal force in this case is equal to the magnitude of tension in the spring.

The formula is :

T= mv²/r where T is tension

m= mass of object =0.8 kg

v= velocity of object {tangential velocity} = 3.0 m/s

r= length of string = 2m

Applying the formula with real values;

T= mv²/r

T= {0.8 * 3²} / 2

T= { 7.2}/2 = 3.6 N

explanation:

newton's third law, for every action there is an equal and opposite reaction.