and 
, respectively.
(1)
- Vector momentum, measured in kilogram-meters per second.
- Mass of the particle, measured in kilograms.
- Vector velocity, measured in meters per second.
and ![\vec v = 2.98\,\hat{i}-3.98\,\hat{j}\,\,\,\left[\frac{m}{s} \right]](/tpl/images/0926/1080/b1898.png)
, then the momentum is:![\vec p = (2.93)\cdot (2.98\,\hat{i}-3.98\,\hat{j})\,\,\,\left[\frac{kg\cdot m}{s} \right]](/tpl/images/0926/1080/520d5.png)
![\vec p = 8.731\,\hat{i}-11.661\,\hat{j}\,\,\,\left[\frac{kg\cdot m}{s} \right]](/tpl/images/0926/1080/e2039.png)
(2) 
(3)
- Magnitude of momentum, measured in kilogram-meters per second. 
- Direction of momentum, measured in sexagesimal degrees.
and 
, then the magnitude and direction of momentum are, respectively:
A 2.93 kg particle has a velocity of (2.98 i hat - 3.98 j) m/s.
Required:
a. Find its x and y...
Physics, 24.11.2020 18:20 tremainewoodley3030
A 2.93 kg particle has a velocity of (2.98 i hat - 3.98 j) m/s.
Required:
a. Find its x and y components of momentum.
b. Find the magnitude and direction of its momentum.
Answers: 3
Another question on Physics
Physics, 22.06.2019 05:30
A2-kg bowling ball is 2.5 meters off the ground on a post when it falls. just before it reaches the ground, it is traveling 7 m/s. assuming that there is no air resistance, which statement is true?
Answers: 3
Physics, 22.06.2019 10:00
Asap and show ! a 14 kg rock starting from rest free falls through a distance of 5.0 m with no air resistance. find the momentum change of the rock caused by its fall and the resulting change in the magnitude of earths velocity. earth mass is 6.0 * 10^24 kg. show your work assuming the rock earth system is closed.
Answers: 2
Physics, 22.06.2019 12:20
What is the coefficient of kinetic friction μk between the block and the tabletop?
Answers: 1
Physics, 22.06.2019 14:00
Amass attached to a spring is displaced from its equilibrium position by 5cm and released. the system then oscillates in simple harmonic motion with a period of 1s. if that same mass–spring system is displaced from equilibrium by 10cm instead, what will its period be in this case? a mass attached to a spring is displaced from its equilibrium position by and released. the system then oscillates in simple harmonic motion with a period of . if that same mass–spring system is displaced from equilibrium by instead, what will its period be in this case? a) 0.5sb) 2sc) 1sd) 1.4s
Answers: 2
You know the right answer?
Questions
Social Studies, 27.10.2021 18:20
Mathematics, 27.10.2021 18:20
Chemistry, 27.10.2021 18:20
English, 27.10.2021 18:20
Mathematics, 27.10.2021 18:20
SAT, 27.10.2021 18:20
Mathematics, 27.10.2021 18:20
Computers and Technology, 27.10.2021 18:20
