10-kg mass at rest on a horizontal frictionless table is accelerated by a force of 20 N. How much work is needed to accelerate the ball to a welocity of 10 m/s?
(A) 5 j
(B) 200j
(C) 500j
(D) 2000j

it should be a

Explanation:

i worked it out

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

e/c, where e is its total energy