A force of 70 N is inclined at an angle of 30° to the horizontal. Calculate its
horizontal and vertical components
respectively.

The horizontal component of the 70 N force = 35·√3 N

The vertical component of the 70 N force = 35 N

Explanation:

The magnitude of the given force, F = 70 N

The angle of inclination of the given force to the horizontal, θ = 30°

By the resolution of forces, we can resolve the given force, F, into its horizontal component, Fₓ, and vertical components, , as follows;

The horizontal component of the given force = Fₓ = F × cos(θ)

Substituting the values, we have;

The horizontal component of the 70 N force, Fₓ = 70 × cos(30°) = 35·√3 N

The vertical component of the given force = = F × sin(θ)

Substituting the values, we have;

The vertical component of the 70 N force, = 70 × sin(30°) = 35 N.

i really dont know but i will try okay.

so i think u would just add all them up and get your answer..