Answer number 19 pls

1. Net force = 90 N

2. Acceleration = 9 m/s²

Explanation:

From the question given above, the following data were obtained:

Mass (m) of bag = 10 Kg

Force applied 1 (Fₐ₁) = 45 N

Force applied 2 (Fₐ₂) = 60 N

Force of friction (Fբ) = 15 N

Net force (Fₙ) =?

Acceleration (a) =?

1. Determination of the net force acting on the bag.

We'll begin by calculating the total force applied on the bag.

Force applied 1 (Fₐ₁) = 45 N

Force applied 2 (Fₐ₂) = 60 N

Total force applied = Fₐ₁ + Fₐ₂

Total force applied = 45 + 60

Total force applied = 105 N

Finally, we shall determine the net force acting on the bag. This is illustrated below:

Total force applied = 105 N

Force of friction (Fբ) = 15 N

Net force (Fₙ) =?

Net force (Fₙ) = Total force applied – Force of friction (Fբ)

Net force (Fₙ) = 105 – 15

Net force (Fₙ) = 90 N to the right

2. Determination of the acceleration of the bag.

Mass (m) of bag = 10 Kg

Net force (Fₙ) = 90 N

Acceleration (a) =?

Force (F) = mass (m) × acceleration (a)

90 = 10 × a

Divide both side by 10

a = 90 / 10

a = 9 m/s²

Thus, the acceleration of the bag is 9 m/s² to the right.

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