To illustrate the use of a multistage rocket consider the following: (a) A certain rocket carries 60% of its initial mass as fuel. (That is, the mass of fuel is 0.6mo) What is the rocket's final speed, accelerating from rest in free space, if it burns all its fuel in a single stage? Express your answer as a multiple of v ex .
(b) Suppose instead it burns the fuel in two stages as follows: In the first stage it burns a mass 0.3m o of fuel. It then jettisons the first-stage fuel tank, which has a mass of 0.1m o , and thenburns the remaining 0.3m 0 of fuel. Find the final speed in this case, assuming the same value of vex throughout and compare.

a

b

Explanation:

Considering question a

From the question we are told that

   The mass of the rocket is    

    The mass of the fuel which is in the rocket is  m = 0.6 M  

Generally given that the rocket burns all it fuel in a single stage , the final velocity of the rocket is mathematically represented as

Here is the mass  of the rocket without fuel which is mathematically evaluated as

=>      

=>    

=>          

=>      

Considering question b

From the question we are told that

   The mass of the fuel it burn at the first stage is  

     The mass of the first stage fuel tank

    The mass of the fuel at the second stage is  

Generally the  velocity of the rocket at the first stage  is mathematically represented as

=>        

=>          

=>        

Generally the mass of the rocket after first stage is  

=>  

Generally the final  velocity of the rocket at the second stage is  

=>  

=>  

=>  

the answer is neither ball has a charge.

because if they were both positively charged, they will repel each other.

if they were positively and negatively charged, they will seek.

search it up!

explanation: