Robin jogs with an average speed of 5.5\,\dfrac{\text m}{\text s}5.5 s m 5, point, 5, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction for 3.3\,\text s3.3s3, point, 3, start text, s, end text.

okay i have so many questions. but the big one here is: um wt..f is this mess? ?

answer: good job it's all correct !

explanation:

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s