Physics, 01.12.2020 20:20 lexybellx3

During a football workout, two linemen are pushing the coach on the sled. The combined mass of the sled and the coach is 300 kg. The coefficient of friction between
the sled and the grass is 0.800. The sled accelerates at the rate of 0.580 m/s^2.
Determine the force applied to the sled by the lineman.

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Answer from: lasagnafoe

F_{players} = 2528.4[N]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body must be equal to the product of mass by acceleration.

On the sled act two forces, the force of friction and The Force executed by the football players.

The movement of the football players will be taken as positive, while the friction will be taken as negative, since it is opposed to the movement of the sled.

ΣF = m*a

where:

F = force [N]

m = mass [kg]

a = acceleration = 0.580 [m/s²]

$F_{players} - f_{friction} = m*a$

The friction force is defected as the coefficient of friction by the normal force, the normal force on a horizontal surface can be calculated as the product of mass by gravitational acceleration.

$f_{friction}=0.8*(300*9.81)\\f_{friction}=2354.4[N]$

Now we can calculate the force exerted by the players.

$F_{players}-2354.5=300*0.580\\F_{players}=2528.4[N]$

Answer from: Quest

hello, i am papaguy.

i have found an answer to your question but use it as information.

information: because weak acids/bases have low concentration of hydrogen ions, the addition of water has a large impact on the ph. 2. a difference in 1 unit is a 10x difference in concentration for example; a liquid with ph of 3 is 10x more acidic than a liquid with a ph of 4. therefore, a liquid with a ph of 3 is stronger.

best of luck!

Answer from: Quest

force is based upon mass and acceleration.the statement is not always true.

it can be explained from newton's second law of motion.

as per newton's second law of motion the rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.

mathematically it can be written as -

$f\alpha \frac{dp}{dt}$

⇒ $f= k \frac{dp}{dt}$

here k is the proportionality constant whose value is 1.

$f=\frac{dp}{dt}$

$f= \frac{d[mv]}{dt}$

$f= m\frac{dv}{dt} +v\frac{dm}{dt}$

$f=ma+v\frac{dm}{dt}$ [a is the acceleration=dv/dt]

hence we see that force not only depends on mass and acceleration but also on velocity and rate of change of mass. force f will depend on mass and acceleration only when mass is constant.

hence the statement that force is based upon mass and acceleration is false.

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