A 2.0-N force is applied to a 1.0 kg book in order to move it across a desk with an acceleration of 0.5 m/s2. Determine the Frictional Force acting on the book.

Make them both to where they have the denominator of 18that makes 3/2 equal 27/18 and 1/9 equal 2/18so now you have  27/18x+5=2/18subtract 5 from the other sideso now you have 27/18x+2/18-5then subtract 2/18 from 27/18 to get 25/18x=-5then divide 25/18 by -5 and your answer will be  -5/18

Answerit increases at a steady rate;