Engine 1 produces twice the power of engine 2. If it takes engine 1 the time T to do the work W, how long does it take engine 2 to do the same work?
Express your answer in terms of some of all of the variables T and W.
T2=

Explanation:

Given that engine 1 produces twice the power of engine 2.

Let and be the power of engine 1 and engine2.

So, the power of the engine 2,

As, Work = Power x time,

So, the work, W, done by an engine 1:

The work, W, done by an engine 2:

If the work done by both the engines are the same, then

[from (ii) nd (iii)]

[by using (i)]

Hence,

d.7.5cm is your answer

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.