An object of volume 7.50×10−4m3 and density 1.15×103kg/m3 is completely submerged in a fluid. Calculate the weight of this object.

The weight of this object is 8.45 N.

Explanation:

Given;

volume of the object, V = 7.5 x 10⁻⁴ m³

density of the object, ρ = 1.15 x 10³ kg/m³

The mass of the object is given as;

mass = density x volume

m = ρV

m = (1.15 x 10³)(7.5 x 10⁻⁴ )

m = 0.8625 kg

The weight of the object is given as;

w = mg

where;

g is acceleration due to gravity = 9.8 m/s²

w = 0.8625 x 9.8

w = 8.45 N

Therefore, the weight of this object is 8.45 N.

diagram is missing, but i will try to explain your doubt.

answer:

amplitude is the maximum displacement or distance moved on a point of a vibrating body or wave measured from its equilibrium position.it is equal to half the length of vibration path.

double the distance = divide strength by 4