Janet jumps horizontally off a high diving platform with a velocity of 2.63 m/s and lands in the water 1.9 s later. How high is the platform

The height of the platform is 22.686 m.

Explanation:

Given;

initial velocity of Janet, u = 2.63 m/s

time of her motion, t = 1.9 s

The height of the platform is given by;

h = ut + ¹/₂gt²

substitute the given values and solve for height "h"

h = (2.63 x 1.9) + ¹/₂(9.8)(1.9)²

h = 4.997 + 17.689

h = 22.686 m

Therefore, the height of the platform is 22.686 m.

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