A shopper in a supermarket pushes a loaded 32 kg cart with a horizontal force of 12 N. a) How far will the cart move in 3.5 s, staring from rest? (Disregard any friction)
b) How far will the cart move in 3.5 s if the shopper places an 85 N child in the cart before pushing?

The answer is  a.first and third quarters 

Not what goes around on earth but the universe too.

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j