Awater tower 30 m tall is located at the top of a hill. from a distance of d = 160 m down the hill, it is observed that the angle formed between the top and base of the tower is 8°. find the angle of inclination of the hill. (round your answer to one decimal place.)

For this we need to use sinus law because there is no right angle in the observed triangle to solve it in some easier way.



where a is height of the water tower, b is length from point of view till bottom of the tower,  is the angle from point of view and  is angle opposite from b.

We use this law to calculate beta angle.






Now we observe different angle. Bottom of the hill-top of the tower-point of view. We calculate angle at point of view (notice how it is different than previous one).

180-90-47.924 = 42.076

At last, the hill inclination is:
42.076 - 8 = 34.076 = 34.1

    5.5 n======    assuming that      we have      m = 0.145 kg    a = 38 m/s²therefore    5.51 n, but two significant figures.final answer: 5.5 n