5. A mass-spring system oscillates with a period of 22 s. What would be the period of the system if the mass and the spring constant were both increased by a factor of four?
O A the period would decrease by half
O B. the period would remain the same
O C the period would be multiplied by the square root of two
O D the period would double

Answer: 1.4 seconds which is the third optionexplanation: current is defined as the flow of charge per timetherefore, the equation that relates current, charge and time can be expressed as follows: i = δq / δtwhere: i is the current given = 1.8 ampereδq is the charge given = 2.5 coulombδt is the time required for the flow of the given charges to give the 1.8 ampere.substitute with the givens in the above equation to get the time as follows: 1.8 = 2.5 / δtδt = 2.5 / 1.8 = 1.38888 which is approximately 1.4 secondshope this was !