Consider the heaviest box of 68 kg that you can push at constant speed across a level floor, where the coefficient of kinetic friction is 0.50, and estimate the maximum horizontal force that you can apply to the box. A box sits on a ramp that is inclined at an angle of 50.0 ∘ above the horizontal. The coefficient of kinetic friction between the box and the ramp is 0.50.

Complete Question

Consider the heaviest box of 68 kg that you can push at constant speed across a level floor, where the coefficient of kinetic friction is 0.50, and estimate the maximum horizontal force that you can apply to the box. A box sits on a ramp that is inclined at an angle of 50.0 ∘ above the horizontal. The coefficient of kinetic friction between the box and the ramp is 0.50.If you apply the same magnitude force, now parallel to the ramp, that you applied to the box on the floor, what is the heaviest box (in pounds) that you can push up the ramp at constant speed? (In both cases assume you can give enough extra push to get the

The force on the heaviest mass  is  

The mass on the inclined ramp is    

Explanation:

From the question we are told that

   The mass of the heaviest box is  

   The coefficient of kinetic friction is  

     The angle at which the ramp is inclined is  

Generally at constant speed the acceleration is zero , which implies that

  Here  F is the horizontal  force applied to the heaviest box   and   is the kinetic frictional  force which is mathematically represented as

=>    

=>    

So

=>            

Considering the ramp inclined at an angle above the horizontal

         Generally apart from the force F  acting on the box in a direction parallel to the ramp the other force acting on the box parallel to the ramp is the net force due to frictional force on the object which is mathematically represented as

and the weight of the object which is mathematically represented as

So the net force is  mathematically evaluated as

=>    

=>    

=>    

So the net force acting on the box parallel to the ramp is  mathematically represented as

=>      

=>      

From the question we are told the velocity is  constant so the acceleration is zero  

   =>      

     =>      

if the person is shown to have +90n, then ans is -10n.

if the person is shown to have -90n, then ans is +10n.

this is an example of "committed" time.

committed time, as contracted time, takes need over essential and available time since it is seen as profitable work. it alludes to the time allotted to keep up a home and family. at the point when a man is commuting using committed time this individual may feel that the drive is an obligation to family, for example, strolling youngsters to class or driving a mate to work. contracted and committed time clients may feel that their commute could really compare to the commute of important or leisure time clients on the grounds that their commute is profitable work. in this manner, they might be more disposed to pick a mechanized method of movement.