If you double the voltage in a circuit and reduce the resistance by a factor of four, what will happen to the current?

By Ohm's Law, we can relate current, voltage and resistance. It is expressed as V=IR. That is, there is a direct relationship between voltage and resistance and voltage and current.

V = IR

V1/2V1 = I1R1 / I2R1/4

1/2 = 4I1/I2

I2 = 8I1

Therefore,  it will increase by a factor of 8. Hope this answers the question.

a) electrical > light, sound, and thermal< < < <

) the mechanical energy of the firefighter moving.< < < < a) electrical > light, sound, and thermal< < < <

c) both a and b.