a person dives off the edge of aa cliff 33m above the surface of the sea. assuming that air resistance is negligible, how long does the dive last and with what speed does the person enter the water

The time is

The speed is

Explanation:

From the question we are told that

    The height of the cliff is  

 Generally from kinematic equation we have that

before the jump the persons initial velocity is  u =  0 m/s

 So

=>      

Generally from kinematic equation

=>  

=>  

scientific laws are the result of testing theories and proving them to be facts.

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s