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a
8
An object moves from point A to point B to point C, then back to point B and then to point Calong the line shown in the figure below.
Okm
1km
2 kom
3km
4km
5km
6km
71cm
8km
9km
10km
11 km
Part A
Find the distance covered by the moving object.
kilometers

d) the number of neutrons plus the number of protons

i really dont know but i will try okay.

so i think u would just add all them up and get your answer..

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft