PLEASE HELP ME QUICK A 10.0 kg dog moving at 6.0 m/s to the right collides with a 5.0 kg cat
moving at 3 m/s to the left. If the cat moves to the right at 12.0 m/s after
the collision, what is the speed of the dog?
O 1.5 m/s to the left
O 1.5 m/s to the right
O 3.0 m/s to the left
0 3.0 m/s to the right

490 n  f=125n a=2.5m/s2

  bv hb ouj bv gv gtrxr

1. electricity2. discharge: )

Distance covered, s = 8ft - 4ft = 4 ftinitial velocity, u = 34 ft/sthe acrobat is moving upwards and therefore, a = -g = -9.81 m/s^2 = 32.19 ft/s^2applying equation of motion; s = ut -1/2gt^2then,4 = 34t -1/2*32.19t^24 = 34t - 16.095t^2rearranging; -16.095t^2 + 34t - 4 = 0solving the quadratic equation; t = {-34 +/- sqrt [34^2 - 4(-16.)]}/2(-16.095) = 1.06 +/- 0.93 = 0.13 or 1.99the acrobat will take 0.13 seconds to be at 8 ft above the ground. additionally, once at the maximum height, the acrobat will move down and be at the same spot (that is height) after 1.99 seconds moving down.