A toy doll and a toy robot are standing on a frictionless surface facing each other. The doll has a mass of 0.2 kg and the robot has a mass of 0.3 kg. The robot pushes on the
doll with a force of 0.3 N. The magnitude of the acceleration of the robot is:

A. Zero
B. 0.60 m/s2
C.1.0 m/s2
D.1.5m/s2

Ithink the answers is b i hope it my friend message me if i’m wrong and i’ll change my answer and fix it for you

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

Answer the above statement is ( false );