Physics, 11.12.2020 04:20 suemmimonjaras8374

A plane is traveling at 80 m/s. To prepare for landing, itslows down at a rate of 0.25 ms squared for 120 seconds. Calculate the speed of the plane after it decelerates. I’ll give brainliest and everything to whoever gets it right please

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Answer from: amm2795

The speed of the plane after it decelerates is 50 m/s

Explanation:

Motion with Constant Acceleration

When an object gains or losses velocity in time, it acquires acceleration. If this value is constant, we can calculate the final velocity (or speed in scalar terms) as:

v_f=v_o+at

Where vf is the final speed, vo is the initial speed, a is the constant acceleration, and t is the time the acceleration is acting.

The plane is originally traveling at vo=80 m/s and it slows down at a constant rate of $a=-0.25\ m/s^2$ during t=120 seconds. Note we have added the negative sign to the acceleration because the plane is slowing down, i.e., the acceleration is against the speed.

Thus, the final speed is:

v_f=80-0.25*120

v_f=80-30=50

$v_f = 50\ m/s$

The speed of the plane after it decelerates is 50 m/s

Answer from: Quest

Iwould sure like to answer your question but i honestly just don’t know

Answer from: Quest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

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