An object is at rest when it undergoes a constant acceleration of 13 m/s2 for 5.0 seconds.
How far will it have traveled during this time?

Hi there!

Find the distance traveled using the kinematic equation:

d = vi(t) + 1/2(a)(t²)

In this instance, vi = 0 because the object was initially at rest. Plug in the other values to solve:

d = 0t + 1/2(13)(5²)

d = 1/2(13)(25)

d = 162.5m

when insulating materials rub against each other, they may become electrically charged . electrons , which are negatively charged, may be 'rubbed off' one material and on to the other. the material that gains electrons becomes negatively charged. the material that loses electrons is left with a positive charge.

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