A hollow aluminum sphere with outer diameter 10.4 cm has a mass of 746 g .What is the sphere's inner diameter?Express your answer with the appropriate units. Din=

the sphere's inner radius is 4.21 cm so the Inner diameter is 8.42 cm

Explanation:

Given that;

mass m = 746 g

diameter d = 10.4 cm

radius r = 5.2 cm

density of aluminum = 2.7 g/cm³

we know that

density × volume = mass

P × 4/3π( r₀³ - ri³) = m

so we substitute

2.7 × 4/3π( 5.2³ - ri³) = 746

11.3097( 5.2³ - ri³) = 746

( 5.2³ - ri³) = 746/11.3097

140.608 - ri³ = 65.961

ri³ = 140.608 - 65.961

ri³ = 74.647

ri = ∛74.647

ri =  4.21 cm

the sphere's inner radius is 4.21 cm so the Inner diameter is 8.42 cm

b

explanation:

bc its just b