Using the rule-of-1 approach, what is the proportional change in centripetal acceleration, ac, for an object in a circular path when the tangential velocity is doubled? 2ac (doubles) 2 A sub c, (doubles) ac2 (halves) the fraction with numerator A sub c and denominator 2, (halves) ac4 (quarters) the fraction with numerator A sub c and denominator 4, (quarters) 4ac (quadruples)

4ac (quadruples)

Explanation:

The general formula for centripetal acceleration is given as follows:

  -------------- equation (1)

where,

ac = centripetal acceleration

v = tangential speed

r = radius of circular path

Now, if we double tangential speed, v' = 2v, then the acceleration will become:

using equation (1):

therefore, the correct answer is:

4ac (quadruples)

a electromagnetic waves

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.