3. A marble with 0.02 kg mass is moving towards right with a velocity of 20 cmys, makes a head on collision with a second marble with a mass of 0.02 kg which is moving towards left with a velocity of 10 cms. After collision the 1st marble moving towards left with a velocity of 10 CM/s, and what is the velocity of 2nd marble after collision?
10 cm/s Left
10 cm/s Right
20 cm/s Right
30 cm/s Right

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s