An object is falling from a height of d and reaches a final velocity of vf. Calculate velocity when the object has fallen a distance d/2.

The final velocity, , is gd.

Explanation:

The condition here is a free falling object. Thus from the third equation of motion under free fall, we have;

= + 2gs

where is the final velocity of the object, is the initial velocity of the object, g is the gravitational force and s is the height.

Since the object falls from a height of d, then = 0 m/s, and s = d.

So that;

= 0 + 2gd

   = 2gd

= 2gd

When the distance is , = 0 m/s.

Then;

= 2g

= g x d

When the object falls through the height , then the final velocity is gd.

r=rho l/a where a is the area, l is the length and rho is resistivity so the greater the area the lesser the resistance thats why the earth pin is thicker bcos current follow the shortest path, so less resistive .

real, smaller and upside-down.   so the answer should be b.