1. Suppose that it takes a simple pendulum 1.2 seconds to swing from its leftmost point to its rightmost point. What is the period of the pendulum? O A 0.6s
OB. 1.2 s
O C.2.4 S
O D. 3.6 s

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490 n  f=125n a=2.5m/s2

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

35.98  million  mile my friend