harold threw a baseball 3 meters harold is 2 meters tall. how fast did he throw the ball and how long was it in the air

u = 7.74 m/s and t = 1.82 s

Explanation:

Given that,

Harold threw a baseball 3 meters.

Harold is 2 meters tall.

The vertical distance = 3m

The final velocity at the maximum height is  0.

Let u is the initial velocity of the baseball. Using the first equation of motion to find it as follows :

Here, a = -g

He has thrown it with the speed of 7.74 m/s

Let t is the time taken by the ball to fall on the ground.

Harold is 2 meters tall. Using second equation of motion to find it.

u = -7.74 (as downward direction is taken as positive)

Hence, this is the required solution.

he . if i may ask what i your question exactly?

explanation:

explanation:

v=uf/(u-f)

= 5.-10/(5+10) convex lens has negative focal length