On an alien planet, a simple pendulum of length 0.400 m has oscillation frequency 0.709 Hz. Find the period of the pendulum. Express your answer with the appropriate units.

1.269 s

Explanation:

The period of oscillation of a simple pendulum is given or expressed with the following relationship

T = 2π√(L/g), where

T is the period of the said pendulum, ?

L is the length of string of the pendulum, 0.4 m

g is the acceleration due to gravity, 9.81 m/s²

On applying the values into the formula, we have

T = 2 * 3.142 * √(0.4/9.81)

T = 6.284 * √0.04077

T = 6.284 * 0.202

T = 1.269 s

Therefore, the period of the pendulum is 1.269 s

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