For an n- channel JFFT, IDSS = 8 mA, and VP = - 6 V. If VGS = - 2 V. What is the value of the drain current ID?

the value of the drain current ID is 3.56 mA

Explanation:

Given that;

IDSS = 8 mA

VP(VGS_OFF) = - 6 V.

VGS = - 2 V

value of the drain current ID = ?

Drain current ID is expressed as;

ID = IDSS [ 1 - (VGS/VP(VGS_OFF)) ]²

we substitute our value

ID = 8 [ 1 - (-2 / -6) ]²

ID = 8 [ 1 - 0.3333 ]²

ID = 8 [ 0.6667 ]²

ID = 8 [ 0.4444 ]

ID = 3.5552 ≈ 3.56 mA

Therefore the value of the drain current ID is 3.56 mA