Calculate the magnetic field strength needed on a 200-turn square loop 20.0 cm on a side to create a maximum torque of 300 N-m if the loop is carrying current of 25.0 A.

The magnetic field strength needed is 1.5 T.

Explanation:

Given;

number of turns, N = 200 turn

length of the each side of the square loop, L = 20 cm = 0.2 m

maximum torque created, τ = 300 N-m

current through the loop, I = 25 A

The maximum torque created in the is the loop is given by;

τ = NIBA

Where;

B is the magnetic field strength, which is calculated as;

Therefore, the magnetic field strength needed is 1.5 T.

note: the given question is incomplete.

complete question is given below.

which is an example of kinetic energy?

a. the energy stored in ethanol  

b. a hockey puck sliding across the ice  

c. a compressed spring  

d. a ball sitting at the top of a ramp

solution: the kinetic energy is the energy posses by the virtue of the motion of the object.

in the given options, a, c and d are the example of potential energy because it is the energy posses by the virtue of the rest of the object. but option b has the kinetic energy as the object is in motion.

hence, a hockey puck sliding across the ice   is the apex example of kinetic energy.

so, the option (b) a hockey puck sliding across the ice   is the correct option.