2. An 873 kg dragster accelerates at a rate of 44.6 m/s during a race. a. What is the magnitude of the net force exerted on the dragster during this time?
Known (Given):
=
Unknown:
Fnet =
Equation:
Fret=ma (or m*a)
Solution:

Explanation:

According to newton's second law:

Force = mass * acceleration

Given

Mass = 873kg

acceleration = 44.66m/s²

Magnitude of the force is expressed as;

F = ma

F = 873 * 44.6

F = 38,673.9N

Hence the magnitude of the net force exerted on the dragster during this time is 38,673.9N

change tension

friction

explanation:

they us to move forward and backwards