Suppose you are in a spacesuit drifting weightless in space some distance away from your spaceship. You have run out of compressed gas for your mini-thruster. Fortunately, you happen to have a bag of baseballs. What can you do to get back to your spaceship? Please give an answer quickly I have to turn this in today.

v = -\frac{n \ m}{M} \ v'

for the man to return to the ship he must throw the balls in the opposite direction of the ship

Explanation:

For this exercise we can use the conservation of momentum. Let's form a system made up of man and baseballs.

Initial instant. Before throwing the balls

     p₀ = 0

Final moment. After throwing the balls

      = M v + n m v '

where M is the mass of the man, m is the mass of each ball and n is the number of balls , v isthe speed man and v' is the speed ball

Since the forces are internal, the momentum of the system is conserved

     p₀ = p_{f}

      0 = M v + n m v ’

If we analyze this expression, for the man to return to the ship he must throw the balls in the opposite direction of the ship

given data:

determine the horse power (h.p) = ?

force applied to move the box(f) = 10 pounds,

box lifted from a distance         (d) = 3 feet

time taken to lift                         (t) = 10 sec,

the horse power is defined as amount of work required to move a load. the horse power is equal to 550 foot-pound per second

                  1 h.p   = 550 foot-pound/second

it can also be defined as the the load that need to be move a body for certain distance in a certain amount of time.

mathematically,

                      h.p = (force × distance)/ time

                            = (10 × 3)/ 10

                            = 30/10

                            = 3 foot -pound/sec

hence, the horse power is needed to move the box is 3 foot-pound/second

important note: 1 h.p = 550 foot-pound/second = 746 watts