Solve Fully and send full answer with calculations. Correct Answer Only.I will be marking the correct answer as brainliest.

● V = IR [Ohm's law]

● Rₙₑₜ = R₁ + R₂ ..... + Rₙ [Series Connection]

● 1/Rₙₑₜ = 1/R₁ + 1/R₂ ..... + 1/Rₙ

[Parallel Connection]

✭ Series Connection :

Both these connection are separated into two series and parallel connection. First two 4 Ω resistance in series and these are connected in parallel

→ R(eq) = R₁ + R₂ ..... + Rₙ

→ R(eq) = 4 + 4

→ R(eq) = 8 Ω

✭ Parallel Connection :

→ 1/Rₙₑₜ = 1/R₁ + 1/R₂ ..... + 1/Rₙ

→ 1/Rₙₑₜ = 1/8 + 1/8

→ 1/Rₙₑₜ = (1+1)/8

→ 1/Rₙₑₜ = 2/8

→ Rₙₑₜ = 8/2

→ Rₙₑₜ = 4Ω

✭ Current when the key is closed :

→ V = IR

→ 2 = I × 4

→ 2/4 = I

→ Current = 0.5 A

━━━━━━━━━━━━━━━━

When the key is open then there would be no current, that is Current = 0 A