A football is kicked at 55o at 15 m/s. How long is it in the air?
How far does it travel to go through the is at the same height as when it started?

I dont even really need the answer I just need the formula to get the answer

A.) T = 1.25s

B.) H = 7.7m

Explanation:

Given that a football is kicked at 55o at 15 m/s.

How long is it in the air?

Let's use the formula below:

V = UsinØ - gt

V = 0 at maximum height.

0 = UsinØ - gt

UsinØ = gt

Substitute all the parameters into the formula

15sin55 = 9.8t

9.8t = 12.29

t = 12.29/9.8

t = 1.25 seconds

How far does it travel to go through the is at the same height as when it started?

That will be the maximum height.

Using the third equation of motion

V^2 = U^2 sin^2ø - 2gH

At maximum height, V = 0

(UsinØ)^2 = 2gH

(15sin55)^2 = 2 × 9.8H

(12.29)^2 = 19.6H

H = 150.97/19.6

H = 7.7 m

molecules are free to separate from each other and will take on the shape of the container. molecules move completely at random and high speeds. they vibrate in a fixed position and do not move around much. molecules expand to the edge of their container.

inverse v=i*r

nice nice