A bus travels at a constant speed. it stops for a short time and then travels at a higher constant speed. draw a distance-time graph for this journey.

See the explanation below

Explanation:

Since the bus travels at a constant speed, we can use the following equation.

where:

x = final position [m]

xo = initial position = 0 (if the bus starts from some reference point)

v = constant velocity [m/s]

t = time [s]

Let's take some data as an example and then graph them.

v = 2 [m/s]

t = 2 [s]

That is, after two seconds, the final position will be:

After the two seconds, the bus stops for about 2 seconds more. Then the bus will go with a velocity of 4 [m/s] for two seconds more.

So the total time is 6 [s].

Let's draw the x-t graph.

And the final offset must be calculated using the same equation.

he kicked it 10 feet straight up into the air? i think this works.

okay i have so many questions. but the big one here is: um wt..f is this mess? ?