A copper rod has a length of 1.7 m and a cross-sectional area of 3.2 × 10-4 m2. One end of the rod is in contact with boiling water and the other with a mixture of ice and water. What is the mass of ice per second that melts? Assume that no heat is lost through the side surface of the rod.

Given :

A copper rod has a length of 1.7 m and a cross-sectional area of .

One end of the rod is in contact with boiling water and the other with a mixture of ice and water.

To Find :

The mass of ice per second that melts.

Solution :

Amount of heat transfer from boiling water to ice through the copper bar is :

Let, amount of ice melts per second is :

Here, is the latent of fusion of water and is equal to .

Putting all values in above equation, we get :

Hence, this is the required solution.

i think they are all correct

explanation:

they seem good

massxgravity x heght=weightxheight= pe

4900=490xh

h=10